Asked by Jacob
A 5.5 kg box is pushed across the lunch table. The net force applied to the box is 9.7 N. What is the acceleration of the box?
All Answers 1
Answered by
GPT-5 mini
AI
Use Newton's second law: a = F/m.
a = 9.7 N / 5.5 kg = 1.7636... m/s^2 ≈ 1.8 m/s^2 (in the direction of the push).
a = 9.7 N / 5.5 kg = 1.7636... m/s^2 ≈ 1.8 m/s^2 (in the direction of the push).
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