Question

On a coordinate plane, a line goes through (1, negative 1) and (4, 2). A point is at (2, 5).
What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (2, 5)?

y + 5 = x + 2
y − 2 = x − 5
y − 5 = −(x − 2)
y + 2 = −(x + 5)

Answer 1

First line slope = (2 − (−1)) / (4 − 1) = 1. Perpendicular slope = −1. Using point-slope with (2,5):

y − 5 = −(x − 2).

So the correct choice is: y − 5 = −(x − 2).