Question

Find the following values. Round to the nearest degree.

S, i, n, left parenthesis, theta, right parenthesis, equals, 0, point, 7, 5, 6, 1Sin(θ)=0.7561
m, angle, theta, equalsm∠θ=
Answer
At

Answer 1

sin(θ) = 0.7561 ⇒ reference angle θ₀ = arcsin(0.7561) ≈ 49.1° ≈ 49°.

Since sine is positive in QI and QII, the angles (0°–360°) are:
θ ≈ 49° or θ ≈ 180° − 49° = 131°.