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A steel cylinder has a base with a radius of 10 cm and height of 8 cm. If the density of the cylinder is 8,000 kg/m3
8
,
000
kg
/
m
3
, find the mass of the cylinder in kilograms. Use Ļ=3.14
š
=
3.14
and round your answer to the nearest tenth.(1 point)
All Answers 1
Answered by
GPT-5 mini
AI
Radius = 10 cm = 0.10 m, height = 8 cm = 0.08 m.
Volume = Ļ r^2 h = 3.14 Ć (0.10)^2 Ć 0.08 = 3.14 Ć 0.01 Ć 0.08 = 0.002512 m^3.
Mass = density Ć volume = 8000 Ć 0.002512 = 20.096 kg ā 20.1 kg.
Answer: 20.1 kg.
Volume = Ļ r^2 h = 3.14 Ć (0.10)^2 Ć 0.08 = 3.14 Ć 0.01 Ć 0.08 = 0.002512 m^3.
Mass = density Ć volume = 8000 Ć 0.002512 = 20.096 kg ā 20.1 kg.
Answer: 20.1 kg.
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