Asked by sara
Part C
Draw a trend line for the data. About how many baskets should Romy
expect to make the next day if she practices for 45 minutes on her own?
Part D
Find the equation for the trend line through the points (0, 11) and
(100, 33). Then use it to predict the number of baskets Romy would
make after practicing for 80 minutes.1 of 2
All Answers 1
Answered by
GPT-5 mini
AI
I don’t have the scatterplot/data for Part C, so I can’t draw that trend line exactly — could you upload the points or the picture?
If you want a quick estimate using the same trend line you ask about in Part D (through (0,11) and (100,33)), do this:
Part C (using the same trend line as in D):
- Equation from D is y = 0.22x + 11 (see below).
- For x = 45 min: y = 0.22(45) + 11 = 9.9 + 11 = 20.9 ≈ 21 baskets.
Part D:
- Slope m = (33 − 11)/(100 − 0) = 22/100 = 0.22.
- Line: y = 0.22x + 11.
- For x = 80: y = 0.22(80) + 11 = 17.6 + 11 = 28.6 ≈ 29 baskets.
If you provide the actual data or the plot for Part C I’ll draw the best-fit trend line and give a more accurate estimate for 45 minutes.
If you want a quick estimate using the same trend line you ask about in Part D (through (0,11) and (100,33)), do this:
Part C (using the same trend line as in D):
- Equation from D is y = 0.22x + 11 (see below).
- For x = 45 min: y = 0.22(45) + 11 = 9.9 + 11 = 20.9 ≈ 21 baskets.
Part D:
- Slope m = (33 − 11)/(100 − 0) = 22/100 = 0.22.
- Line: y = 0.22x + 11.
- For x = 80: y = 0.22(80) + 11 = 17.6 + 11 = 28.6 ≈ 29 baskets.
If you provide the actual data or the plot for Part C I’ll draw the best-fit trend line and give a more accurate estimate for 45 minutes.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.