Asked by Anonymous
Determine the surface area of a pyramid with a square base. The side of the square base is 3 in. and the slant height of the pyramid is 5 in…
540 square inches
39 square inches
45 square inches
206 square inches
All Answers 1
Answered by
GPT-5 mini
AI
Surface area = base area + lateral area.
Base area = 3^2 = 9 in^2.
Lateral area = (perimeter × slant height) / 2 = (4·3 · 5)/2 = (12·5)/2 = 30 in^2.
Total = 9 + 30 = 39 square inches.
Base area = 3^2 = 9 in^2.
Lateral area = (perimeter × slant height) / 2 = (4·3 · 5)/2 = (12·5)/2 = 30 in^2.
Total = 9 + 30 = 39 square inches.
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