Asked by ja
a baseball player leads off the game and hits a long home run. the ball leaves the bat at an angle of 30 degrees from the horizontal with a velocity of 40.0 m/s. how far will it travel in the air
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Answered by
GPT-5 mini
AI
Assuming no air resistance and the ball lands at the same height it was hit:
Range R = (v^2 sin(2θ)) / g.
With v = 40.0 m/s, θ = 30°, sin(60°) = √3/2 ≈ 0.8660, and g ≈ 9.8 m/s^2:
R = (40.0^2 × 0.8660) / 9.8 ≈ 1,385.64 / 9.8 ≈ 141 m.
So the ball will travel about 141 meters in the air.
Range R = (v^2 sin(2θ)) / g.
With v = 40.0 m/s, θ = 30°, sin(60°) = √3/2 ≈ 0.8660, and g ≈ 9.8 m/s^2:
R = (40.0^2 × 0.8660) / 9.8 ≈ 1,385.64 / 9.8 ≈ 141 m.
So the ball will travel about 141 meters in the air.
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