Question

What is the slope-intercept form of the equation of the line that passes through the point (–6, 1) and is perpendicular to the graph of 2x + 3y = –5?

y = x – 8
y = x + 1
y = x + 1
y = x + 10

Answer 1

First find the slope of 2x + 3y = −5: y = (−2/3)x − 5/3 so m1 = −2/3. A perpendicular slope is m2 = 3/2.

Use point-slope with (−6,1): y − 1 = (3/2)(x + 6) → y = (3/2)x + 10.

None of the given choices match; the correct equation is y = (3/2)x + 10.