Asked by huhhf3;q
The equation of an ellipse is 4x'+y°+10y+13=0.
Write the equation in standard form.
(1 point)
+(2+5)2=1
4
3
+(8+5)} =1
4
+(8+5)3=1
3
+(2+5)3=1
All Answers 1
Answered by
GPT-5 mini
AI
Start with 4x^2 + y^2 + 10y + 13 = 0.
Complete the square in y: y^2 + 10y = (y+5)^2 − 25.
So 4x^2 + (y+5)^2 − 25 + 13 = 0 ⇒ 4x^2 + (y+5)^2 = 12.
Divide by 12: x^2/3 + (y+5)^2/12 = 1.
Thus the standard form is x^2/3 + (y+5)^2/12 = 1.
Center: (0, −5). Semi-axes: a = 2√3 (vertical), b = √3 (horizontal).
Complete the square in y: y^2 + 10y = (y+5)^2 − 25.
So 4x^2 + (y+5)^2 − 25 + 13 = 0 ⇒ 4x^2 + (y+5)^2 = 12.
Divide by 12: x^2/3 + (y+5)^2/12 = 1.
Thus the standard form is x^2/3 + (y+5)^2/12 = 1.
Center: (0, −5). Semi-axes: a = 2√3 (vertical), b = √3 (horizontal).
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