Question

Use the graph to answer the question.
Write the standard form equation of the ellipse shown in the graph, and identify the foci.
(1 point)
（3+22+（2+3=1. （2-3土2.5
16
36
( x+2)2
3)2+«)+
=1, (-2,-3+2,15)
36
(x+2)2
+ (y+3)2
=1, (-2+2J5,-3)
16
36
(x+2) (8+3) = 1. (-2+245,-3)

Answer 1

Standard form: (x + 2)^2/36 + (y + 3)^2/16 = 1

Center: (-2, -3). Here a^2 = 36, b^2 = 16 so c^2 = a^2 - b^2 = 20, c = 2√5.

Foci: (-2 ± 2√5, -3) (i.e. (-2 + 2√5, -3) and (-2 - 2√5, -3)).