Question

Find the center and radius of the circle represented by the following equation: x*+(y+4)°=3.
(1 point)
center: (0,-4) ; r=V3
center: (0,-4) ; r = 3
center: (0,4) ; r=J3
center: (0,4) ; r= 3

Answer 1

Equation is x^2 + (y+4)^2 = 3, which is (x-0)^2 + (y-(-4))^2 = (√3)^2.
So center = (0, -4) and radius = √3.