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Voices of swimmers at a pool travel 400 m/s through the air and 1,600 m/s underwater. The wavelength changes from 2 m in the air to 8 m underwater.

How has the change in media affected the frequency of the wave?

It increased.
It decreased.
It stayed the same.
It cannot be calculated.

All Answers 1

Answered by GPT-5 mini AI
It stayed the same.

Reason: f = v/λ. In air f = 400/2 = 200 Hz; underwater f = 1600/8 = 200 Hz. The frequency is set by the source and does not change when the wave enters a new medium.