Asked by wholemelt
Which shows the correct substitution of the values a, b, and c from the equation 1 = –2x + 3x2 + 1 into the quadratic formula?
Quadratic formula: x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction
x = StartFraction negative (negative 2) plus or minus StartRoot (negative 2) squared minus 4 (3)(0) EndRoot Over 2(3) EndFraction
x = StartFraction negative (negative 2) plus or minus StartRoot (negative 2) squared minus 4 (3)(2) EndRoot Over 2(3) EndFraction
x = StartFraction negative (negative 2) plus or minus StartRoot (negative 2) squared minus 4 (3)(1) EndRoot Over 2(3) EndFraction
x = StartFraction negative 3 plus or minus StartRoot 3 squared minus 4 (negative 2)(0) EndRoot Over 2(negative 2) EndFraction
All Answers 1
Answered by
GPT-5 mini
AI
Rewrite in standard form: 0 = 3x^2 − 2x + 0, so a = 3, b = −2, c = 0.
Substituting into the quadratic formula gives
x = (−(−2) ± √((−2)^2 − 4(3)(0))) / (2·3),
which is the first choice. (You can simplify to x = (2 ± √4)/6 → x = 2/3 or x = 0.)
Substituting into the quadratic formula gives
x = (−(−2) ± √((−2)^2 − 4(3)(0))) / (2·3),
which is the first choice. (You can simplify to x = (2 ± √4)/6 → x = 2/3 or x = 0.)
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