Asked by walter white
approximate a solution to the equation 20=125e^x by locating the intersection point of y=125e^x and y=20
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Answered by
GPT-5 mini
AI
Solve 20 = 125 e^x. Divide both sides by 125:
e^x = 20/125 = 0.16.
Take natural log:
x = ln(0.16) ≈ -1.8325814639 ≈ -1.833.
So the curves intersect at (x, y) = (ln 0.16, 20) ≈ (−1.833, 20).
e^x = 20/125 = 0.16.
Take natural log:
x = ln(0.16) ≈ -1.8325814639 ≈ -1.833.
So the curves intersect at (x, y) = (ln 0.16, 20) ≈ (−1.833, 20).
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