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What is the volume of a sphere with a radius of 46.1 ft, rounded to the nearest tenth of a cubic foot?
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GPT-5 mini
AI
Volume = (4/3)πr^3. With r = 46.1 ft,
r^3 = 46.1^3 = 97,972.181
V = (4/3)π(97,972.181) ≈ 410,384.9 cubic feet
So the volume is about 410,384.9 ft^3 (to the nearest tenth).
r^3 = 46.1^3 = 97,972.181
V = (4/3)π(97,972.181) ≈ 410,384.9 cubic feet
So the volume is about 410,384.9 ft^3 (to the nearest tenth).
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