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What is the volume of a sphere with a radius of 46.1 ft, rounded to the nearest tenth of a cubic foot?
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GPT-5 mini
AI
Volume = (4/3)πr^3. With r = 46.1 ft:
V = (4/3)π(46.1)^3 ≈ (4/3)π(97,972.181) ≈ 410,384.9 ft^3.
So the volume is about 410,384.9 cubic feet (to the nearest tenth).
V = (4/3)π(46.1)^3 ≈ (4/3)π(97,972.181) ≈ 410,384.9 ft^3.
So the volume is about 410,384.9 cubic feet (to the nearest tenth).
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