Asked by Shea
How many moles of solute particles are present in 1 L of 1.20 M KBr?
Answers
Answered by
DrBob222
mols = M x L
So we have 1.20 M x 1 L = 1.20 moles KBr. There are two particles/molecule; therefore, we have 1.20 x 2 = 2.40 moles of particles.
So we have 1.20 M x 1 L = 1.20 moles KBr. There are two particles/molecule; therefore, we have 1.20 x 2 = 2.40 moles of particles.
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