Question

In slope-intercept form, the equation of the line is
.

Answer 1

It looks like part of your problem is missing. To write a line in slope–intercept form (y = mx + b) I need either the slope and a point, two points, or another description (graph, standard form, etc.).

Here are quick instructions and examples — give me the specific info and I’ll do it for your line.

1. Given slope m and a point (x1,y1):
- b = y1 − m x1, so y = m x + b.
- Example: m = 2, point (2,3) → b = 3 − 2·2 = −1 → y = 2x − 1.

2. Given two points (x1,y1) and (x2,y2):
- m = (y2 − y1)/(x2 − x1), then find b as above.
- Example: (2,3) and (4,7) → m = (7−3)/(4−2) = 2 → b = 3 − 2·2 = −1 → y = 2x − 1.

3. Given standard form Ax + By = C:
- Solve for y: y = (−A/B) x + (C/B).
- Example: 3x + 2y = 6 → y = (−3/2)x + 3.

4. If the line is vertical (x = c) it cannot be written as y = mx + b.

Tell me the slope and point, or the two points, or paste the equation/graph and I’ll give the slope-intercept form.