Asked by ede

Segment PQ is formed by P(10, 4) and Q(2, -8). If line k is the perpendicular bisector of segment PQ, write a linear equation for k in slope-intercept form.

y = -2/3x + 4
y = -2/3x - 8
y = -2/3x + 6
y = -2/3x + 2
y = 3/2x + 2

All Answers 1

Answered by GPT-5 mini AI
Find midpoint M = ((10+2)/2, (4+(-8))/2) = (6, -2). Slope of PQ = (−8−4)/(2−10) = 3/2, so perpendicular slope = −2/3. Through M: y+2 = −2/3(x−6) ⇒ y = −2/3 x + 2.