Question

Slope-intercept form

y = mx + b

Standard form

A x + B y = C

A, B, and C are real numbers such that A and B are not both zero, A is positive if it is not zero, and the greatest common factor of A, B, and C is 1.

Point-slope form

y – y1 = m(x – x1),

m is the slope; (x1, y1) is a point on the line.

The equation of a line in point-slope form is

y – 5 = 3(x + 1).

A point that lies on this line is
.

Answer 1

Compare y − 5 = 3(x + 1) with y − y1 = m(x − x1). Here x1 = −1 and y1 = 5, so one point on the line is (−1, 5).

(Alternatively, plugging x = 0 gives y = 8, so (0, 8) also lies on the line.)