Question

Write the equation of the line that is perpendicular to the line 5x + 6y = 18 and passes through the point (10, 7).

y = 6/5x - 3
y = -5/6x - 5
y = 6/5x - 5
y = 6/5x + 5
y = 6/5x + 19

Answer 1

First find the slope of 5x + 6y = 18: y = (-5/6)x + 3, so its slope is -5/6. A perpendicular slope is 6/5.
Using point-slope through (10,7): y - 7 = (6/5)(x - 10) ⇒ y = (6/5)x - 5.

So the correct choice is: y = 6/5x - 5.