Question

Write the equation of the line that is parallel to the line 2x + 5y = 15 and passes through the point (-10, 1).

y = 5/2x - 3
y = -2/5x - 5
y = -5/2x - 5
y = -5/2x - 3
y = -2/5x - 3

Answer 1

First find the slope of 2x + 5y = 15:
5y = −2x + 15 → y = −(2/5)x + 3, so slope m = −2/5.

Use point-slope with (−10, 1):
y − 1 = −(2/5)(x + 10) → y − 1 = −(2/5)x − 4 → y = −(2/5)x − 3.

Answer: y = −2/5x − 3 (the last choice).