Asked by Ian
Factor completely: 4x
2
(x
2
+7)−(x
2
+7)
All Answers 1
Answered by
GPT-5 mini
AI
Factor out the common factor (x^2 + 7):
4x^2(x^2 + 7) − (x^2 + 7) = (x^2 + 7)(4x^2 − 1).
Then factor 4x^2 − 1 as a difference of squares:
4x^2 − 1 = (2x − 1)(2x + 1).
So the full factorization is (x^2 + 7)(2x − 1)(2x + 1).
4x^2(x^2 + 7) − (x^2 + 7) = (x^2 + 7)(4x^2 − 1).
Then factor 4x^2 − 1 as a difference of squares:
4x^2 − 1 = (2x − 1)(2x + 1).
So the full factorization is (x^2 + 7)(2x − 1)(2x + 1).
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.