Question

The scatter plot shows the amount of time Adam spent studying and
his test scores. Use the scatter plot for Items 2–4.
2. What relationship do you see between the amount of time spent
studying and the test scores? Is the relationship linear? Lesson 4-1
𝖠 In general, Adam scores higher on a test when he spends more time
studying. There is not a linear relationship.
𝖡 In general, Adam scores higher on a test when he spends more time
studying. There is a positive linear relationship.
𝖢 In general, Adam scores lower on a test when he spends more time
studying. There is a negative linear relationship.
𝖣 In general, Adam scores lower on a test when he spends more time
studying. There is not a relationship.
3. Use the y-intercept and the point (4, 90) from the line on the scatter plot.
What is the equation of the linear model? Lesson 4-3
4. Predict Adam’s test score when he studies for 6 hours. Lesson 4-3
5. Describe the relationship between the data in the scatter plot. Lesson 4-

Answer 1

I don’t have the scatter plot image, but I can answer and show how to get the exact equation/prediction if you give the y‑intercept (the point where the line crosses the y‑axis). Meanwhile:

2) The relationship is that Adam generally scores higher when he spends more time studying — it’s a positive linear relationship. (Choice B.)

3) Let the y‑intercept be b (the point (0,b)). Using the point (4, 90), the slope is m = (90 − b)/(4 − 0) = (90 − b)/4. So the linear model is
y = [(90 − b)/4] x + b.
(If you tell me the numeric y‑intercept I’ll give the numeric equation.)

4) Predicted score at x = 6 hours:
y(6) = [(90 − b)/4]·6 + b = 135 − 0.5b.
(Again, give b and I’ll compute the numeric prediction.)

Example: if the y‑intercept is 70, then slope = (90−70)/4 = 5, equation y = 5x + 70, and y(6) = 5·6 + 70 = 100.

5) Describe the relationship: The data show a positive (increasing) linear association — as study time increases, test scores tend to increase. The points appear to follow a straight-line trend (strong/moderate positive correlation depending on how tightly they cluster).