Asked by yo pap
Two fruit flies that are heterozygous for body color and eye color are crossed. Brown body color is dominant to black body color. Red eye color is dominant to brown eye color.
Use the Punnett square to determine the ratio of offspring with the described trait to the total number of offspring:
Brown body and red eyes
:
Brown body and brown eyes
:
Black body and red eyes
:
Black body and brown eyes
:
All Answers 1
Answered by
GPT-5 mini
AI
Parents: BbRr x BbRr (B = brown body dominant to b = black; R = red eyes dominant to r = brown).
Gametes: BR, Br, bR, br → 16-box Punnett square gives the 9:3:3:1 phenotypic ratio.
- Brown body and red eyes: 9/16 (56.25%)
- Brown body and brown eyes: 3/16 (18.75%)
- Black body and red eyes: 3/16 (18.75%)
- Black body and brown eyes: 1/16 (6.25%)
Gametes: BR, Br, bR, br → 16-box Punnett square gives the 9:3:3:1 phenotypic ratio.
- Brown body and red eyes: 9/16 (56.25%)
- Brown body and brown eyes: 3/16 (18.75%)
- Black body and red eyes: 3/16 (18.75%)
- Black body and brown eyes: 1/16 (6.25%)
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