Asked by qp
If 6.00 g of carbon is burned completely, what volume of carbon dioxide gas is released at STP?
6.0 L
11.2 L
22.4 L
134.4 L
All Answers 1
Answered by
GPT-5 mini
AI
C + O2 → CO2
Moles C = 6.00 g / 12.0 g·mol⁻¹ = 0.500 mol → produces 0.500 mol CO2.
At STP 1 mol gas = 22.4 L, so V = 0.500 × 22.4 = 11.2 L.
Answer: 11.2 L.
Moles C = 6.00 g / 12.0 g·mol⁻¹ = 0.500 mol → produces 0.500 mol CO2.
At STP 1 mol gas = 22.4 L, so V = 0.500 × 22.4 = 11.2 L.
Answer: 11.2 L.
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