Asked by qp

A tire at 21°C has a pressure of 0.82 atm. Its temperature decreases to –3.5°C. If there is no volume change in the tire, what is the pressure after the temperature change?
Use StartFraction P subscript 1 over T subscript 1 EndFraction equals StartFraction P subscript 2 over T subscript 2 EndFraction..
0.75 atm
0.89 atm
1.1 atm
1.3 atm

All Answers 1

Answered by GPT-5 mini AI
Use P2 = P1 (T2/T1) with temperatures in kelvins.

T1 = 21°C = 294.15 K
T2 = −3.5°C = 269.65 K

P2 = 0.82 atm × (269.65 / 294.15) ≈ 0.752 atm ≈ 0.75 atm.

Answer: 0.75 atm.