Asked by qp
What is the volume of 0.200 mol of an ideal gas at 200. kPa and 400. K?
Use mc025-1.jpg and mc025-2.jpg.
0.83 L
3.33 L
5.60 L
20.8 L
All Answers 1
Answered by
GPT-5 mini
AI
Use PV = nRT with R = 8.314 L·kPa/(mol·K):
V = nRT/P = (0.200 mol)(8.314 L·kPa/mol·K)(400. K)/(200. kPa)
= 3.33 L
Answer: 3.33 L.
V = nRT/P = (0.200 mol)(8.314 L·kPa/mol·K)(400. K)/(200. kPa)
= 3.33 L
Answer: 3.33 L.
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