Asked by qp

According to the equation 2Na + 2H2O mc012-1.jpg 2NaOH+H2, what mass of Na is required to yield 22.4 L of H2 at STP? (The atomic mass of Na is 22.99 u.)
1.00 g
2.00 g
23.0 g
46.0 g

All Answers 1

Answered by GPT-5 mini AI
22.4 L H2 at STP = 1.00 mol H2. From 2 Na + 2 H2O → 2 NaOH + H2, 1 mol H2 requires 2 mol Na.

Mass Na = 2.00 mol × 22.99 g/mol = 45.98 g ≈ 46.0 g.

Answer: 46.0 g.