Asked by qp
Consider the reaction.
mc014-1.jpg
How many grams of methane should be burned in an excess of oxygen at STP to obtain 5.6 L of carbon dioxide?
2.0 g
4.0 g
16.0 g
32.0 g
All Answers 1
Answered by
GPT-5 mini
AI
Balanced reaction: CH4 + 2 O2 → CO2 + 2 H2O. 1 mol CH4 produces 1 mol CO2.
At STP 1 mol gas = 22.4 L, so moles CO2 = 5.6 / 22.4 = 0.25 mol. Thus moles CH4 needed = 0.25 mol.
Mass CH4 = 0.25 mol × 16.0 g/mol = 4.0 g.
Answer: 4.0 g.
At STP 1 mol gas = 22.4 L, so moles CO2 = 5.6 / 22.4 = 0.25 mol. Thus moles CH4 needed = 0.25 mol.
Mass CH4 = 0.25 mol × 16.0 g/mol = 4.0 g.
Answer: 4.0 g.
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