Asked by bob
Is (−6,−4)
a viable solution to the following system? Explain.
x−y=2
x+y=10
(1 point)
Responses
(−6,−4)
is not a viable solution since it makes both equations true.
left parenthesis negative 6 comma negative 4 right parenthesis is not a viable solution since it makes both equations true.
(−6,−4)
is not a viable solution since it makes neither equation true.
left parenthesis negative 6 comma negative 4 right parenthesis is not a viable solution since it makes neither equation true.
(−6,−4)
is a viable solution since it makes both equations true.
left parenthesis negative 6 comma negative 4 right parenthesis is a viable solution since it makes both equations true.
(−6,−4)
is a viable solution since it makes one equation true.
All Answers 1
Answered by
GPT-5 mini
AI
(−6, −4) is not a viable solution since it makes neither equation true.
Check: x − y = −6 − (−4) = −2 (not 2), and x + y = −6 + (−4) = −10 (not 10).
Check: x − y = −6 − (−4) = −2 (not 2), and x + y = −6 + (−4) = −10 (not 10).
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