Question

How many real solutions does the following quadratic equation have?

25x2+60x+36=0
25
𝑥
2
+
60
𝑥
+
36
=
0

(1 point)
solution(s)

Answer 1

Compute the discriminant: Δ = b^2 − 4ac = 60^2 − 4·25·36 = 3600 − 3600 = 0.
Since Δ = 0, there is exactly 1 real solution (a repeated root): x = −b/(2a) = −60/(50) = −6/5.