Question

At what temperature (oC) will a gas sample occupy 6.1 L if it originally occupies 17.8 L at 27.1oC?


I did (v1/t1)=(v2)/(t2)
v1=17.8
v2=6.1
t1=27.1 C = 300.25 K

the answer i got for t2= 102.894 K which would be -170.106 C
This doesnt seem right is it?

Answer 1

Same answer I have but you're only allowed two significant figures with the 6.1 in there (unless that's really 6.10 and you just omitted the last zero). If that's true, then 3 s.f. and I would round to -170 C.