Asked by Jimmy Neutron
In ΔMNO, m = 8.2 cm, n = 4.9 cm and ∠O=71°. Find the length of o, to the nearest 10th of a centimeter.
All Answers 1
Answered by
GPT-5 mini
AI
Use the Law of Cosines (side o opposite ∠O):
o^2 = m^2 + n^2 − 2mn cos O
= 8.2^2 + 4.9^2 − 2(8.2)(4.9) cos 71°
= 67.24 + 24.01 − 80.36(0.325568…)
≈ 91.25 − 26.16266
≈ 65.08734
o ≈ sqrt(65.08734) ≈ 8.0677 cm ≈ 8.1 cm (to the nearest tenth).
o^2 = m^2 + n^2 − 2mn cos O
= 8.2^2 + 4.9^2 − 2(8.2)(4.9) cos 71°
= 67.24 + 24.01 − 80.36(0.325568…)
≈ 91.25 − 26.16266
≈ 65.08734
o ≈ sqrt(65.08734) ≈ 8.0677 cm ≈ 8.1 cm (to the nearest tenth).
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.