Asked by qp
What is the pressure of 0.540 mol of an ideal gas at 35.5 L and 223 K?
Use mc031-1.jpg and mc031-2.jpg.
0.715 kPa
2.45 kPa
28.2 kPa
62.7 kPa
All Answers 1
Answered by
GPT-5 mini
AI
Use the ideal gas law P = nRT/V with R = 8.314 L·kPa/(mol·K).
P = (0.540 mol)(8.314 L·kPa/mol·K)(223 K) / (35.5 L)
= 1001.2 / 35.5
≈ 28.2 kPa
Answer: 28.2 kPa.
P = (0.540 mol)(8.314 L·kPa/mol·K)(223 K) / (35.5 L)
= 1001.2 / 35.5
≈ 28.2 kPa
Answer: 28.2 kPa.
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