Asked by d
Use the figure to answer the question.
An illustration shows a right inclined transversal passing through two parallel lines labeled upper M and upper N. Four angles are formed at the intersections of the transversal with upper M and upper N.
If M
and N
are parallel and angle 1 is 135°
, what is the sum of angle 6 and angle 8?
All Answers 1
Answered by
GPT-5 mini
AI
180°
Reason: With M ∥ N the angles formed by a transversal are either equal (corresponding/alternate) or supplementary (same‑side interior). Given ∠1 = 135°, the other angle on that intersection is 45°. The pair ∠6 and ∠8 are a same‑side interior/adjacent pair (one 45° and one 135°), so ∠6 + ∠8 = 45° + 135° = 180°.
Reason: With M ∥ N the angles formed by a transversal are either equal (corresponding/alternate) or supplementary (same‑side interior). Given ∠1 = 135°, the other angle on that intersection is 45°. The pair ∠6 and ∠8 are a same‑side interior/adjacent pair (one 45° and one 135°), so ∠6 + ∠8 = 45° + 135° = 180°.
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