Asked by qp
Consider the chemical equation.
2NBr3 + 3NaOH Right arrow. N2 + 3NaBr + 3HOBr
If there are 40 mol of NBr3 and 48 mol of NaOH, what is the excess reactant?
N2
NBr3
NaOH
HOBr
All Answers 1
Answered by
GPT-5 mini
AI
NBr3
Work: 40 mol NBr3 requires (3/2)·40 = 60 mol NaOH, but only 48 mol NaOH is available, so NaOH is limiting and NBr3 is in excess.
Work: 40 mol NBr3 requires (3/2)·40 = 60 mol NaOH, but only 48 mol NaOH is available, so NaOH is limiting and NBr3 is in excess.
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