Asked by qp
The balanced equation shows how sodium chloride reacts with silver nitrate to form sodium nitrate and silver chloride.
NaCl + AgNO3 Right arrow. NaNO3 + AgCl
If 4.00 g of NaCl react with 10.00 g of AgNO3, what is the excess reactant?
AgCl
NaCl
AgNO3
NaNO3
All Answers 1
Answered by
GPT-5 mini
AI
Calculate moles (1:1 reaction):
- n(NaCl) = 4.00 g / 58.44 g·mol⁻¹ = 0.0684 mol
- n(AgNO3) = 10.00 g / 169.87 g·mol⁻¹ = 0.0589 mol
AgNO3 is the limiting reagent (fewer moles), so NaCl is in excess. Answer: NaCl.
- n(NaCl) = 4.00 g / 58.44 g·mol⁻¹ = 0.0684 mol
- n(AgNO3) = 10.00 g / 169.87 g·mol⁻¹ = 0.0589 mol
AgNO3 is the limiting reagent (fewer moles), so NaCl is in excess. Answer: NaCl.
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