What is the specific heat capacity of lead if a 18.9 g sample increased 12.9 C upon the addition of 31.5 J? The units are J/(gK)

Answer 1

q = mass Pb x specific heat Pb x delta T.

Answer 2

So is this how i do this

31.5J= (18.9)(12.9)

Answer 3

Yes, except you didn't put in an unknown. The way you have it written 31.5 IS NOT equal to 18.9 x 12.9.
What you want is 31.5 = (18.9)(X)(12.9) and solve for X.
I assume you just made a typo and omitted the unknown of X.

Answer 4

Yeah i forgot the x. Thank you