Asked by Anthony

What is the specific heat capacity of lead if a 18.9 g sample increased 12.9 C upon the addition of 31.5 J? The units are J/(gK)
Answered by DrBob222
q = mass Pb x specific heat Pb x delta T.
Answered by Anthony
So is this how i do this

31.5J= (18.9)(12.9)







Answered by DrBob222
Yes, except you didn't put in an unknown. The way you have it written 31.5 IS NOT equal to 18.9 x 12.9.
What you want is 31.5 = (18.9)(X)(12.9) and solve for X.
I assume you just made a typo and omitted the unknown of X.
Answered by Anthony
Yeah i forgot the x. Thank you
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