Asked by b
Mr. Shaw graphs the function f(x) = –5x + 2 for his class. The line contains the point (-2, 12). What is the point-slope form of the equation of the line he graphed?
y – 12 = –5(x + 2)
y – 12 = 2(x + 2)
y + 12 = 2(x – 2)
y + 12 = –5(x – 2)
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y − 12 = −5(x + 2)
Using point-slope form y − y1 = m(x − x1) with m = −5 and (x1,y1) = (−2,12): y − 12 = −5(x − (−2)) = −5(x + 2).
Using point-slope form y − y1 = m(x − x1) with m = −5 and (x1,y1) = (−2,12): y − 12 = −5(x − (−2)) = −5(x + 2).
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