Question

A football is thrown with an initial upward velocity component of 15.0 m/s and a horizontal velocity component of 18.0 m/s
The time required for the football to reach the highest point in its trajectory is 1.53s.
It gets 11.5m above the ground.

How much time after it is thrown does it take to return to its original height?
How far has the football traveled horizontally from its original position?

Answer 1

you are given time to get to top, it takes the same time to fall down.

how far=horizontal velocity*timeinair

Answer 2

1.53 seconds to get to highest point so 1.53x2 to reach the end of the porabola. 3.06 seconds

Answer 3

Jade you got to remember that it is accelerating downwards since gravity is -9.8 m/s. so it is not easy as that and I would think before you try and put your knowledge on the page.

Answer 4

Actually, Jacob, jade is 100% right as it is taught this way to save time but you can go the long way if you would like.