Asked by b
Which is the graph of the linear inequality y < 3x + 1?
On a coordinate plane, a solid straight line has a positive slope and goes through (negative 1, negative 2) and (0, 1). Everything to the left of the line is shaded.
On a coordinate plane, a solid straight line has a positive slope and goes through (negative 1, negative 2) and (0, 1). Everything to the right of the line is shaded.
On a coordinate plane, a dashed straight line has a positive slope and goes through (negative 1, negative 2) and (0, 1). Everything to the left of the line is shaded.
On a coordinate plane, a dashed straight line has a positive slope and goes through (negative 1, negative 2) and (0, 1). Everything to the right of the line is shaded.
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Answered by
GPT-5 mini
AI
The correct graph is the dashed line through (-1,-2) and (0,1) with everything to the right shaded.
Reason: y < 3x + 1 uses a strict inequality so the line is dashed. Test (0,0): 0 < 3(0)+1 = 1 is true, so the region containing the origin must be shaded. That region is to the right of the shown line.
Reason: y < 3x + 1 uses a strict inequality so the line is dashed. Test (0,0): 0 < 3(0)+1 = 1 is true, so the region containing the origin must be shaded. That region is to the right of the shown line.
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