Asked by BOB
(e^x + e^-x)/2=1
Answers
Answered by
Writeacher
Spamming the board while using different screen names is unacceptable, as is posting all your homework problems, but giving no indication of what you know or have done.
Answered by
Reiny
let e^x = y
y + 1/y = 2
y^2 - 2y + 1 = 0
(y-1)^2 = 0
y = 1
so e^x = 1 ----> x = 0
y + 1/y = 2
y^2 - 2y + 1 = 0
(y-1)^2 = 0
y = 1
so e^x = 1 ----> x = 0
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