Asked by mike
How much work must you do to push a 10 kg block of steel across a steel table friction is 0.6 at a steady speed of 1.3 m/s for 9.8 s?
Answers
Answered by
bobpursley
do you mean the coefficent of sliding friction is .6?
at steady speed, 1.3m/s, figure how far the block goes (distance) in 9.8s
work= forcefriction*distance=mu*mg*distance
at steady speed, 1.3m/s, figure how far the block goes (distance) in 9.8s
work= forcefriction*distance=mu*mg*distance
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