Asked by sara
Think About the Process Why is a data point with an x-coordinate of 0 a good point to use when creating a trend line for a data set? The graph shows the altitude of a weather balloon over time. The trend line passes through the points (0,474) and (10,563). Write the equation of a trend line for the data shown in the graph. After how many minutes is the balloon at an altitude of 527.4 feet above sea level?
Balloon Elevation
0
5
10
520
440
600
Time (min)
Altitude (ft)
x y graph
Question content area bottom
Part 1
Why is a data point with an x-coordinate of 0 a good point to use when creating a trend line for a data set? Select all that apply.
A.
The y-coordinate of this point is the y-intercept.
B.
The y-coordinate of this point is always positive.
C.
The coordinates of this point are both 0.
D.
It is easy to compute the slope using this point.
All Answers 1
Answered by
GPT-5 mini
AI
Part 1 — Select all that apply:
A and D.
- A is true because a point with x = 0 gives the y-intercept.
- D is true because using x = 0 simplifies the slope calculation (you subtract 0).
- B is false (the y-value need not be positive).
- C is false (x = 0 does not imply y = 0 unless the point is the origin).
Trend line:
Slope m = (563 − 474)/(10 − 0) = 89/10 = 8.9, so the equation is
y = 8.9x + 474.
When y = 527.4:
527.4 = 8.9x + 474 → x = (527.4 − 474)/8.9 = 53.4/8.9 = 6.
The balloon is at 527.4 ft after 6 minutes.
A and D.
- A is true because a point with x = 0 gives the y-intercept.
- D is true because using x = 0 simplifies the slope calculation (you subtract 0).
- B is false (the y-value need not be positive).
- C is false (x = 0 does not imply y = 0 unless the point is the origin).
Trend line:
Slope m = (563 − 474)/(10 − 0) = 89/10 = 8.9, so the equation is
y = 8.9x + 474.
When y = 527.4:
527.4 = 8.9x + 474 → x = (527.4 − 474)/8.9 = 53.4/8.9 = 6.
The balloon is at 527.4 ft after 6 minutes.
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