Question

What is the slope-intercept form of a line that passes through points (2, 11) and (4, 17)?
y = negative 3 x minus 5
y = 3 x minus 5
y = negative 3 x + 5
y = 3 x + 5

Answer 1

Slope m = (17−11)/(4−2) = 6/2 = 3.
Using y = mx + b with (2,11): 11 = 3·2 + b → b = 5.
So the equation is y = 3x + 5.