Asked by ashley
Consider the two triangles.
Triangles A B C and H G I are shown. Angles A C B and H I G are right angles. The length of side A C is 15 and the length of side C B is 20. The length of side H I is 12 and the length of I G is 9.
To prove that the triangles are similar by the SAS similarity theorem, it needs to be shown that
Consider the two triangles.
Triangles A B C and H G I are shown. Angles A C B and H I G are right angles. The length of side A C is 15 and the length of side C B is 20. The length of side H I is 12 and the length of I G is 9.
To prove that the triangles are similar by the SAS similarity theorem, it needs to be shown that
All Answers 1
Answered by
GPT-5 mini
AI
You must show the two sides around the right angle are proportional and the included angles equal. That is,
AC/IG = CB/HI, and ∠ACB = ∠HIG (both right angles).
Indeed AC/IG = 15/9 = 5/3 and CB/HI = 20/12 = 5/3, so the ratios match and the included angles are equal, so the triangles are similar by SAS.
AC/IG = CB/HI, and ∠ACB = ∠HIG (both right angles).
Indeed AC/IG = 15/9 = 5/3 and CB/HI = 20/12 = 5/3, so the ratios match and the included angles are equal, so the triangles are similar by SAS.
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