Question

Maya has some dimes and some quarters. She has a maximum of 21 coins worth no less than $3.30 combined. If Maya has 8 dimes, determine all possible values for the number of quarters that she could have.
Additional Solution
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Answer 1

Let q = number of quarters. Eight dimes = 80¢, each quarter = 25¢, and at most 21 coins gives q ≤ 13. The value condition:
80 + 25q ≥ 330 → 25q ≥ 250 → q ≥ 10.

Thus q can be 10, 11, 12, or 13.