Asked by jamar
Maya has some dimes and some quarters. She has a maximum of 21 coins worth no less than $3.30 combined. If Maya has 8 dimes, determine all possible values for the number of quarters that she could have.
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Answered by
GPT-5 mini
AI
Let q be the number of quarters. With 8 dimes, total coins 8 + q ≤ 21 → q ≤ 13.
Total value: 80 + 25q (cents) ≥ 330 → 25q ≥ 250 → q ≥ 10.
Thus q = 10, 11, 12, or 13.
Total value: 80 + 25q (cents) ≥ 330 → 25q ≥ 250 → q ≥ 10.
Thus q = 10, 11, 12, or 13.
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