Asked by bob
WHICH ONE DOESNβT BELONG? Use the discriminant to determine which of these equations is different from the others.
A. π₯2 β3β’π₯ β40 =0
B. 12β’π₯2 βπ₯ β6 =0
C. 12β’π₯2 +2β’π₯ β4 =0
D. 7β’π₯2 +6β’π₯ +2 =0
Equation 1 of 3.
Select Choice
is different from the other 3 equations because it has 2 2 of 3.
Select Choice
roots, where the other 3 equations each have 2 irrational, complex, or rational roots?
All Answers 1
Answered by
GPT-5 mini
AI
Compute discriminants D = b^2 β 4ac:
A: a=1, b=β3, c=β40 β D = 9 β 4(1)(β40) = 169 (>0, perfect square) β two distinct rational real roots.
B: a=12, b=β1, c=β6 β D = 1 β 4(12)(β6) = 289 (>0, perfect square) β two distinct rational real roots.
C: a=12, b=2, c=β4 β D = 4 β 4(12)(β4) = 196 (>0, perfect square) β two distinct rational real roots.
D: a=7, b=6, c=2 β D = 36 β 4(7)(2) = β20 (<0) β two complex (nonreal) conjugate roots.
So choice D is different: it has two complex (nonreal) roots, while A, B, and C each have two real rational roots.
A: a=1, b=β3, c=β40 β D = 9 β 4(1)(β40) = 169 (>0, perfect square) β two distinct rational real roots.
B: a=12, b=β1, c=β6 β D = 1 β 4(12)(β6) = 289 (>0, perfect square) β two distinct rational real roots.
C: a=12, b=2, c=β4 β D = 4 β 4(12)(β4) = 196 (>0, perfect square) β two distinct rational real roots.
D: a=7, b=6, c=2 β D = 36 β 4(7)(2) = β20 (<0) β two complex (nonreal) conjugate roots.
So choice D is different: it has two complex (nonreal) roots, while A, B, and C each have two real rational roots.
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